Design Problem EE517 Fall 2000 Revision 6
Parts 1) through 12) are due November 21, 2000 and
parts 13) through 24) are due November 28, 2000.
You are to design a 2-pole, 3-phase, synchronous motor that will be supplied power from a 440Vrms (line to line) 60Hz source. The armature windings are Y connected. The rating of the motor is 2.5HP.The maximum allowed magnetic flux density at any point in the iron and at any time is Bmax = 1.65Tesla. The maximum rms current density in the copper at rated conditions is Jrmsrated = 350A/cm2. You are to design the machine so that the DC field current is 0.1 times the peak armature current. The minimum allowed air gap is 0.02 inches to insure it is not to difficult to build the machine. You may assume the machine is sinusoidally wound. You may use the design factors and the values given in table 1. To complete your design you must compute the quantities in table 2. All dimensions are to be given in inches though it is recommended that all calculations be done using MKS units.
|
Design Factor Definition |
Value |
|
Kw = Winding factor, fraction of the rotor and stator slot area occupied by copper. |
0.25 |
|
a dslot = depth of slot / radius to the air gap (rotor radius) |
0.333 |
|
a length = stack length / radius to the air gap |
1.167 |
|
a %slot = percent (fraction) of the rotor or stator circumference occupied by slots |
0.5 (50%) |
|
NaIa = NfIf |
Table 1 Design factors and their values
Answer the following questions as you do your design.
|
Design Results |
Value |
|
Rg = radius to the air gap = rotor radius |
2.572 in |
|
Dg = rotor diameter |
5.145 in |
|
g = air gap |
0.0499 in |
|
Awa = 2 AW3 f = total area required for the stator (armature) windings |
6.922 in2 |
|
Ds = diameter to the bottom of the stator slot |
6.858 in |
|
Awf = total area required for the rotor (field) windings |
2.569 in2 |
|
Dr = Diameter to the bottom of the rotor slot |
3.873 |
|
Dshaft = largest allowed shaft diameter |
1.301 |
|
Dout = outside diameter of the stator |
9.43 in |
|
lstk = stack length = axial length of iron. |
3.002 in |
|
aw = area of the wire |
1.954 10-3 in2 |
|
Wire gauge |
# 16 |
|
Na = number of stator (armature) turns per phase |
148 |
|
Nf = number of rotor (field turns) |
1,480 |
|
Rph = resistance of one stator phase winding |
1.275 W |
Table 2 Design results to be computed.
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where Bfgmax is the peak B field due to the field winding in time and space neglecting the effect of the slots.
|
Slot No. |
Phase A turns |
Phase B turns |
Phase C turns |
Sum |
|
1 |
17+ |
50- |
32+ |
99 |
|
2 |
44+ |
44- |
5+ & 5- (10 wires) |
98 |
|
3 |
50+ |
17- |
32- |
99 |
|
4 |
32+ |
17+ |
50- |
99 |
|
5 |
5+ & 5- (10 wires) |
44+ |
44- |
98 |
|
6 |
32- |
50+ |
17- |
99 |
|
7 |
50- |
32+ |
17+ |
99 |
|
8 |
44- |
5+ & 5- (10 wires) |
44+ |
98 |
|
9 |
17- |
32- |
50+ |
99 |
|
Total (half machine) |
148 |
148 |
148 |
444 / 2 |
Summary of stator turns
|
Slot No. |
Field turns |
|
1 |
173+ |
|
2 |
438+ |
|
3 |
499+ |
|
4 |
325+ |
|
5 |
45+ & 45- (90 wires) |
|
6 |
325- |
|
7 |
499- |
|
8 |
438- |
|
9 |
173- |
|
Total (half machine) |
1480 |
Summary of rotor turns